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Template format error: Each Parameters member should be an object. | by Teri Radichel | Bugs That Chew | Sep, 2022


This error is just not clear. Let me attempt to assist …

PSA: Test the online for plagiarism of something you publish on-line. Now onto our weblog put up…

This error occurred in a template I used to be deploying lately. It’s the tiniest of errors that causes a deployment to fail and on this case the error message is totally unclear. I instantly figured it out however for a more moderen programmer I might guess this error is senseless. In reality, it actually doesn’t make sense to me however I get why the one who wrote it may need written it the way in which they did.

If you end up writing error messages you shouldn’t write them from the attitude of the code you might be working with behind the scenes. It is best to write them from the attitude of the one who will get the error message and inform them precisely the best way to repair the issue.

It appears to me that the individual writing the error ought to be capable of get a deal with on the parameter identify inflicting the error. Then, if there may be not a correctly formatted line that signifies the kind of the parameter, give the precise syntax that may resolve the issue.

On this case I had written an AWS CloudFormation template parameter like this:

Parameters:
UserNameParam:
Kind:String

Can you see the error?

Does β€œTemplate format error: Each Parameters member should be an object” present a transparent description of the issue and the best way to repair it? Sure, you may need shortly figured it out if you’re an skilled programmer like me, however contemplate what a greater description of this downside is perhaps.

I might assume it could be one thing like this:

The parameter UserNameParam is lacking the β€œKind” property or the road setting the kind is just not correctly formatted. The right formatting is an indentation adopted by β€œKind: [Your type here]”.

The issue in my code above is one little house lacking after the colon. The repair for the code seems to be like this:

Parameters:
UserNameParam:
Kind: String

Teri Radichel

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