#embody <bits/stdc++.h>
utilizing namespace std;
void find_most_duplicates(vector<int>& A)
{
int N = A.measurement();
vector<pair<int, int> > freq;
unordered_map<int, int> mp;
for (int i = 0; i < A.measurement(); i++) {
mp[A[i]]++;
}
for (auto i : mp) {
freq.push_back({ i.second, i.first });
}
int max_freq = 0, X = 0, m = freq.measurement();
if (m == 1) {
max_freq = freq.again().first;
X = 0;
}
else if (m == 2) {
max_freq = freq[0].first + freq[1].first;
X = abs(freq[0].second - freq[1].second);
}
else {
int first_greatest = 0, second_greatest = 0;
int first_greatest_index = -1,
second_greatest_index = -1;
for (int i = 0; i < m; i++) {
if (freq[i].first > first_greatest) {
swap(first_greatest, second_greatest);
swap(first_greatest_index,
second_greatest_index);
first_greatest = freq[i].first;
first_greatest_index = i;
}
else if (freq[i].first > second_greatest) {
second_greatest = freq[i].first;
second_greatest_index = i;
}
}
max_freq = first_greatest + second_greatest;
X = abs(freq[first_greatest_index].second
- freq[second_greatest_index].second);
}
cout << "X = " << X
<< ", Most Frequency Potential = " << max_freq
<< endl;
}
int foremost()
{
vector<int> A{ 2, 1, 3, 3, 4, 5 };
find_most_duplicates(A);
return 0;
}
