Like arrays, Linked Listing is a linear knowledge construction. In contrast to arrays, linked listing parts usually are not saved at a contiguous location; the weather are linked utilizing pointers. They embrace a collection of related nodes. Right here, every node shops the info and the deal with of the following node.
To study extra about linked listing seek advice from the article “Introduction to Linked LIst“.
Given a linked listing, the duty is to insert a brand new node after a given node of the linked listing.
Insert new node after a given node in linked listing
Instance:
Listing = 1->2->4->5, Insert a node with worth 3 after the node with worth 2.
Output listing will likely be: 1->2->3->4->5
Think about the next representations of the linked listing.
C++
class Node {
public:
int knowledge;
Node* subsequent;
};
|
C
struct Node {
int knowledge;
struct Node* subsequent;
};
|
Java
class LinkedList {
Node head;
class Node {
int knowledge;
Node subsequent;
Node(int d)
{
knowledge = d;
subsequent = null;
}
}
}
|
Python3
class Node:
def __init__(self, knowledge):
self.knowledge = knowledge
self.subsequent = None
class LinkedList:
def __init__(self):
self.head = None
|
C#
public class Node {
public int knowledge;
public Node subsequent;
public Node(int d)
{
knowledge = d;
subsequent = null;
}
}
|
Javascript
<script>
var head;
class Node {
constructor(d) {
this.knowledge = d;
this.subsequent = null;
}
}
</script>
|
Method: Observe the under steps for inserting a node after a given node:
- Firstly, verify if the given earlier node is NULL or not.
- Then, allocate a brand new node (say temp) and
- Assign the info to temp.
- After which make the following of temp as the following of the earlier node.
- Lastly, transfer the following of the earlier node to level to temp.
Observe the under picture for a greater understanding.
Find out how to insert a brand new node after given node in linked listing
Beneath is the implementation of the strategy.
C++
void insertAfter(Node* prev_node, int new_data)
{
if (prev_node == NULL) {
cout << "The given earlier node can't be NULL";
return;
}
Node* new_node = new Node();
new_node->knowledge = new_data;
new_node->subsequent = prev_node->subsequent;
prev_node->subsequent = new_node;
}
|
C
void insertAfter(struct Node* prev_node, int new_data)
{
if (prev_node == NULL) {
printf("the given earlier node can't be NULL");
return;
}
struct Node* new_node
= (struct Node*)malloc(sizeof(struct Node));
new_node->knowledge = new_data;
new_node->subsequent = prev_node->subsequent;
prev_node->subsequent = new_node;
}
|
Java
public void insertAfter(Node prev_node, int new_data)
{
if (prev_node == null) {
System.out.println(
"The given earlier node can't be null");
return;
}
Node new_node = new Node(new_data);
new_node.subsequent = prev_node.subsequent;
prev_node.subsequent = new_node;
}
|
Python3
def insertAfter(self, prev_node, new_data):
if prev_node is None:
print("The given earlier node should inLinkedList.")
return
new_node = Node(new_data)
new_node.subsequent = prev_node.subsequent
prev_node.subsequent = new_node
|
C#
public void insertAfter(Node prev_node, int new_data)
{
if (prev_node == null) {
Console.WriteLine("The given earlier node"
+ " can't be null");
return;
}
Node new_node = new Node(new_data);
new_node.subsequent = prev_node.subsequent;
prev_node.subsequent = new_node;
}
|
Javascript
<script>
operate insertAfter(prev_node, new_data)
{
if (prev_node == null)
{
doc.write("The given earlier node can't be null");
return;
}
var new_node = new Node(new_data);
new_node.subsequent = prev_node.subsequent;
prev_node.subsequent = new_node;
}
</script>
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Time Complexity: O(1)
Auxiliary House: O(1)
